If you start at 2, and count by 3s, you get the sequence:
2, 5, 8, 11
There's a general form for this arithmetic sequence which looks like:
an = a1 + d(n - 1)
where an is the nth term, a1 is your first term, d is your common difference and n is what term number you're looking for.
a50 would equal...
a50 = 2 + 3(50-1)
a50 = 2 + 3 * 49
a50 = 149
Kaylie L.
01/21/16