Andrew M. answered • 12/15/15

Tutor

New to Wyzant
Mathematics - Algebra a Specialty / F.I.T. Grad - B.S. w/Honors

Parallel lines have the same slope

so you are looking for the equation of

the line through (-2,-1) that has the

same slope as that of the line through

(-2,-2), (0,6)

For the slope we use m = rise/run

or (change in y)/(change in x)

m = (6-(-2))/(0-(-2))

m = 8/2 = 4

We have the slope m=4 and point (-2,-1)

Slope intercept form is y=mx+b

y = 4x + b

Solve for b using x=-2, y = -1 from the given point

-1 = 4(-2) + b

-1 = -8 + b

7 = b

Your equation for the line is

**y = 4x + 7**Hope this helps. Let me know if you have questions.

Katie C.

could you also help me with this problem as well?

Find the equations of the lines through the following pairs of points, in slope intercept form.

(1) Find the equation of the line through (5,3),(−4,4).

y=

(2) Find the equation of the line through (2,−2),(5,3).

y=

y=

(2) Find the equation of the line through (2,−2),(5,3).

y=

Report

12/15/15

Andrew M.

1. This is done exactly as in the original problem. Use your points (5,3) and (-4,4) to find the slope.

m = (4-3)/(-4-5) = -1/9

with he slope m and either of the two given points you can find the equation in form y=mx+b.

At this point we have y = (-1/9)x + b

Again, you can use either point... I will use (5,3) as the (x,y) values to solve for b.

3=(-1/9)(5) + b

3 = -5/9 + b

3+5/9 = b

27/9 + 5/9 = b

32/9 = b

your line is: y = (-1/9)x + 32/9

Try the next one yourself.

Good luck with your class.

Report

12/16/15

Katie C.

12/15/15