On a buying trip Rosario ordered 120 prices of jewelry: a number of bracelets at $4 and a number of necklaces at $15. She paid $1360 how many bracelets?

Question

I need to find the number of bracelets and necklaces she purchased 

Answer 1

Hi Allyssa, 

We can solve this problem through the following steps: 

Step One: Translate our problem into equations

Since we know that Rosario has 120 pieces total, we can say:

Let x=the number of bracelets

Let 120-x= the number of necklaces

Step Two: Create an equation to relate our let statements to the item prices

4x+15(120-x)=1360 Solve for x

4x+1800-15x=1360 Distribute

-11x+1800=1360 Combine Like Terms

-11x=1360-1800 Subtract both sides by 1800

-11x=-440 Divide both sides by -11

x=440

∴Rosario has 440 bracelets.

Best, 

Star

Answer 2

We know that N + B = 120  --> necklaces plus bracelets equals total amount of jewelry

We also know that 15N + 4B = 1360 --> 15 dollars per necklace plus 4 dollars per bracelet equals total price of 1360.

 

So plug the first equation into the second equation, after rearranging it to get B = 120 -N

15N + 4(120 - N) = 1360

15N + 480 - 4N = 1360

11N + 480 = 1360

11N = 1360 - 480 = 880

N = 880/11  = 80

So B = 120 - 80 = 40

So 80 necklaces and 40 bracelets