3x-4(2x+5)=-16 +13x

Question

Seems easy, but...I want to be sure I am using the correct order

Thanks

 

C

Answer 1

Follow order of operations. WAIT, can't combine 2x+5, BUT we can DISTRIBUTE something. So distribute to EVERYTHING in the ( ) then combine like terms to get -5x-20=-16+13x   Now get anything with an x on ONE side. Then get x all by itself. Finally x=(-2/9)

Answer 2

3x-4(2x+5)=-16 +13x

1.remove parentheses  3x-8x-20=-16+13x

-5x-20=-16+13x  2. add 5x to both sides get -20=-16+18x

3. add 16 to both sides get -4=18x

4. divide by 18 get -4/18=-2/9=x

Answer 3

Multiplication comes before subtraction, so first you must distribute 4(2x+5). Also you must remember to subtract both terms from 3x. After this step you end up with 3x-8x-20=-16+13x. Next you put all x terms together and all constants together. If you put all constants on the left and x terms on the right, you end up with -4=18x. Dividing both sides by 18, you get x=-4/18=-2/9.

Answer 4

3x-4(2x+5)=-16+13x

 

You have to first multiply 2x+5 by -4 before you can begin combining the other terms.

-4*(2x+5)=-8x-20 so...

 

3x-8x-20=-5x-20=-16+13x

 

then add 16 to both sides and add 5x to both sides

-5x+5x-20+16=-16+16+13x+5x

-20+16=13x+5x

-4=18x

 

divide both sides by 18

-4/18=18x/18=x

-2/9=x