Jack N.

asked • 11/04/15

Please help me with the following mathematical question.

Rescue Option 2: Rescue Boat

There is a rescue boat that is already out at sea at R. However, it receives distress calls from the yacht and another boat, at the same time.
The rescue boat must go to the nearest distress call first.
The boat is located at B, 350 km away, on a bearing of 120°T from R.
The yacht is located at Y on a bearing of 210°T and 170 km away from B.
 
 
 
a) Show that ∠RBY is a right-angle.
i. The North/South lines at R and B are parallel lines. Use your knowledge of co-interior angles to find: ∠PBR = ___°

ii. Using the number of degrees in a revolution, show ∠RBY = 90°
 
Thanks so much

1 Expert Answer

By:

Tristan N. answered • 11/04/15

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Jack N.

Thank you so much Tristan. That helped heaps. I have a couple more questions if you would be so kind. 
 
b) Use Pythagoras to calculate the distance from the rescue ship to the yacht.
i) Draw the right-angled triangle showing all lengths.
ii) Calculate the required distance to the nearest kilometre.

The nearest distress call is the __________ .

4. Calculate how long it will take the recue ship to reach the yacht.

If it takes 10 hours to reach the people on the boat at B:

a) What is the speed of the rescue boat?

The formula to use is: Speed=Distance/time



b) In hours and the nearest minute, how long will it take the rescue boat to get from B to Y?



c) After reaching B it took 45 minutes to get the people on board.
i. What is the total time it would take the rescue boat to reach the stranded yacht going from R to B to Y?
ii. What is the total distance travelled by the rescue boat?
Report

11/04/15

Tristan N.

For part b, since we've proven that the angle between the rescue boat and the yacht (as measured frim the other boat) is 90 degrees, all you need to do is use the Pythagorean Theorem to calculate RY. In this case, RY = sqrt(350^2 + 170^2). I will leave it as an exercise to carry out the actual multiplication.
 
Regardless of your answer, the nearest distress call is going to always be to the boat, because the hypotenuse of a right triangle (in this case, RY) is always going to be the longest leg.
 
Therefore, for the next problem, use the distance RB divided by the time it takes to get there to attain the average speed. In this case, 350km / 10 hours yields an average speed of 35kph.
 
If the boat then travels at 35kph to get to the yacht, the time it takes to traverse BY will be distance/speed or 170km / 35kph. Again, I will leave it as an exercise for you to deal with the actual numbers.
 
For the last question, take the 10 hours of transit across RB, add 45 minutes, then add your answer from the last question.
 
The total distance traveled is going to be 350+170=520.
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11/05/15

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