You know the function is x4. You can assume this from the original function if f(2)=16 then it has to be x4
So f(a)=16
f'(a) = 4x3
f'(a)=4(2)3= 32
The formula is
f(a)+f'(a)(x-a)
16+32(x-2) You said 1.999 was what you were trying to evaluate so
16+32(1.999-2)
= 16 +32(-.001)
This gives me a value of 15.968