Svetlana Z. answered 10/27/15
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The hyperbolic functions have very similar properties to their trigonometric counterparts. They satisfy the following relations:
cosh(x)2 - sinh(x)2 = 1
sech(x) = 1/cosh(x)
csch(x) = 1/sinh(x)
tanh(x) = sinh(x)/cosh(x)
coth(x) = 1/tanh(x)
Using these relations we have and the fact that cosh(x) = 5/3, we have:
1. (5/3)2 - sinh(x)2 = 1
sinh(x)2 = (5/3)2 -1 = 25/9 - 1 = 16 / 9
then sinh(x) = sqrt(16/9) = 4/3
2. sech(x) = 1/cosh(x) = 1/(5/3) = 3/5
3. csch(x) = 1/sinh(x) = 1/(4/3) = 3/4
4. tanh(x) = sinh(x)/cosh(x) = (4/3) /(5/3) = 4/5
5. coth(x) = 1/tanh(x) = 1/(4/5) = 5/4