Arthur D. answered 10/05/13
Tutor
4.9
(296)
Forty Year Educator: Classroom, Summer School, Substitute, Tutor
1) x=4y+3
2x+5y=-7
2(4y+3)+5y=-7
8y+6+5y=-7
13y+6=-7
13y=-6-7
13y=-13
y=-1
x=4(-1)+3
x=-4+3
x=-1
(-1,-1)
check: 2(-1)+5(-1)=-7
-2+(-5)=-7
-7=-7
-1=4(-1)+3
-1=-4+3
-1=-1
4) 2x-y=-15
5x+6y=5
2x-y=-15
-y=-2x-15
y=2x+15
substitute now
5x+6(2x+15)=5
5x+12x+90=5
17x+90=5
17x=-85
x=-5
5x+6y=5
5(-5)+6y=5
-25 +6y=5
6y=30
y=5
solution: (-5,5)
You try 2) and 3) !
Good Luck !