The graph shows the lines 5x+4y=7 and x-3y=9. Based on the graph, estimate the solution of the system of equations:

5x+4y=7

x-3y=9

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1st equation in slope intercept form is: y = (-5/4)X + 7/4

2nd equation y = (1/3)X - 3

A graph would show them intersecting in the 4th quadrant.

to solve the two equations:

5X + 4Y = 7

X - 3Y = 9

mult 2nd eqn by -5 and add the two eqn to elim X

5X + 4Y = 7

-5X + 15Y = -45

-----------------------

0X + 19Y = -38 so Y = -38/19 or Y = -2 <----

subst Y = -2 in either eqn, I'll do the 2nd eqn, to find X

X - 3(-2) = 9 or X + 6 = 9 or X = 3 <----

so the solution, which is the intersection point of the 2 lines is at (3,-2)

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