Bruce Y. answered 10/16/15
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33The first one is a cubic polynomial of the form A3+B3, which factors into (A+B)(A2-AB+B2)
In this case, A = 2x and B = 3 (because (2x)3=8x3 and 33=27
So 8x3+27 = (2x+3)((2x)2-(2x)(3)+32) = (2x+3)(4x2-6x+9)
For the second one, don't forget that the first step of every factoring problem is to factor out the GCF, if there is one. In this case, each term is a multiple of 2x, so we factor that out, getting
16x4-2x = 2x(8x3-1) We recognize 8x3 as being (2x)3, and 1 as being 13, so we see this as being of the form A3-B3, which can also be factored.
16x4-2x = 2x(8x3-1) = 2x(2x-1)(4x2+2x+1)
As with all factoring problems, you should multiply your results to see if you get the original expressions.