3 consecutive integers have a sum of 57. What are the 3 integers

Question

 i am doing algebra and i need help with this math problem

Answer 1

Let x=integer # 1; then, x + 1= 2^nd integer; and x + 2= 3^rd integer.

 

x + (x + 1) + (x + 2) = 57

 

3x + 3 = 57

 

3x = 54

 

x₁ = 18.

x₂ = x + 1 = 18 + 1 = 19

x₃ = x + 2 = 18 + 2 = 20

 

Check: 18 + 19 + 20 = 57 and, they are consecutive.

Answer 2

Here's what we know:

a + b + c = 57

a = b - 1

c = b + 1

 

Now that we have values for our variables, let's put them in:

(b - 1) + b + (b + 1) = 57

Simplify:

3b = 57

Divide both sides by 3:

b = 19

a = 19 - 1

a = 18

c = 19 + 1

c = 20

 

Check:

18 + 19 + 20 = 57

57 = 57