Mary Donna A. answered • 09/10/13

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For every 1 teacher, there are 10 students.

Assuming there are are 447 students this would be a probability question.

Therefore you can set the ratios equal to each other where x = the number of teachers.

1/10 = x/447

So we isolate the x by multiplying each side of the equation to 447

(1/10) * 447 = (x/447) * 447

447/10 = x

44.7 = x

We then round this answer to the nearest whole number, since we can't have .7 of a teacher.

45 = x = # of teachers.

If we are assuming number of students enrolled is y + 447 because of " 447 MORE students enrolled last year", then,

1/10 = x/(y+447)

Solve for x for # of teachers, and

solve for y for # of students.

Isolate each variable..

x = (1/10) x (y+447)

= (y+447)/10

for y:

1/10 = x/(y+447) (cross multiply)

/x /x

(1/10)/x = 1(y+447)

10x = y+447

-447 -447

10x-447 = y