For every 1 teacher, there are 10 students.
Assuming there are are 447 students this would be a probability question.
Therefore you can set the ratios equal to each other where x = the number of teachers.
1/10 = x/447
So we isolate the x by multiplying each side of the equation to 447
(1/10) * 447 = (x/447) * 447
447/10 = x
44.7 = x
We then round this answer to the nearest whole number, since we can't have .7 of a teacher.
45 = x = # of teachers.
If we are assuming number of students enrolled is y + 447 because of " 447 MORE students enrolled last year", then,
1/10 = x/(y+447)
Solve for x for # of teachers, and
solve for y for # of students.
Isolate each variable..
x = (1/10) x (y+447)
1/10 = x/(y+447) (cross multiply)
(1/10)/x = 1(y+447)
10x = y+447
10x-447 = y