Andrew M. answered 08/14/15
Tutor
New to Wyzant
Mathematics - Algebra a Specialty / F.I.T. Grad - B.S. w/Honors
I assume you need to find the cost of a pair of pants, a sweater, and a shirt...
Let P = cost of pants
Let B = cost of a shirt (blouse)
Let S = cost of a sweater
We have 3 equations and 3 variables from the table as given:
eqn 1) 5P + 5B + 2S = 377
eqn 2) 5P + 6B = 322
eqn 3) 3P + 7B + 3S = 408
Let's take eqn1 and eqn 2 and eliminate the P variable
Multiply eqn 2 by -1 and add the result to eqn 1
5P + 5B + 2S = 377 eqn 1
-5P - 6B = -322 eqn 2(-1)
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-B + 2S = 55
Now let's use eqn 2 and eqn 3 to eliminate the P variable again
-15P - 18B = -966 eqn 2(-3)
15P + 35B + 15S = 2040 eqn 3(5)
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17B + 15S = 1074
I now have two equations with two variable that I can use to solve for B and S
-B + 2S = 55
17B + 15S = 1074
We will follow the same process to eliminate one variable and solve for the other
I will multiply the 1st by 17 to eliminate the B variable when I add the results
-17B + 34S = 935
17B + 15S = 1074
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49S = 2009
S = 2009/49
S = 41
We now have the cost of a sweater... Substitute 41 in place of S
in the equation -B + 2S = 55 or 17B + 15S = 1074 to solve for B
I will use -B + 2S = 55
-B + 2(41) = 55
-B + 82 = 55
-B = 55-82
-B = -27
B = 27
We now have the cost of a sweater S=41 and the cost of a shirt B=27
Substitute those values back into one of the original 3 equations to find
the cost of a pair of pants:
I'll use equation 2: 5P + 6B = 322
5P + 6(27) = 322
5P + 162 = 322
5P = 322-162
5P = 160
P = 32
A pair of pants costs $32
A shirt costs $27
A sweater costs $41