distance S (in feet) traveled byvehiclestop to the time T in seconds s(t)=16t^{2} skid marks to determine the braking distance was about 650 feet.What is the

Question

The following formula relates the distance S (in feet) traveled by a vehicle during an emergency stop to the time T (in seconds) it takes to arrive at a complete stop: s(t)=16t^{2}

At the scene of an accident, Bill uses skid marks to determine the braking distance of one of the vehicles involved was about 650 feet.

What is the corresponding braking time in seconds?

Answer 1

             as t given that braking distance is related to time by the function : s(t)=16t^{2}

          S(t)= 650

             So to find t we use the above function.

          650  =  16t²

          650/16 =  t²

                 50 =  t²

            √(50) =  t

 

                    t=7.07 sec

 

So the breaking time will be 7.07 sec