Pam is 14 and her dad is 37. in how many years will Pam's dad be twice as old as she will be?

Question

Please help 

Answer 1

23 and 46: 9 years from now.

 

It has to be odd years later because whenever you double the number, it becomes even.  Since 37 is odd, a half of Dad's age is between 18 and 19. 

 

So, we know that Pam's age must pass 19 years old (5 years) which it makes her Dad's age 42 by adding 5 to each.  Next even number for Dad's age is 44 which makes Pam's age 21 by adding 7. 

 

Next even number for Dad's age is 46 which makes Pam's age 23 by adding 9.  And 46 is twice the number of 23.

 

Pam = 23, Pam's Dad = 46  (after 9 years)

 

I hope you understand how I did it.

 

Yohan C.   (LV  NV)

 

 

Answer 2

If x years go by from now, Pam's age will be 14 + x and her Dad's age will be 37 + x. We want the number of years after which Pam's Dad's age is twice her age, or

 

2(x+14)=x+37

 

We need to solve this equation for x. First, distribute the 2 on the left hand side of the equation:

 

2x+2*14=2x+28=x+37

 

Now subtract x from both sides:

 

x+28=37

 

Subtract 28 from both sides to get x by itself:

 

x=37-28=9.

 

So Pam's dad will be twice as old as her in 9 years. (Pam will be 14+9=23 years old and her dad will be 37+9=46 years old.)