Abel H.

asked • 06/17/13

which fact is not sufficient to show that planes R and S are perpendicular?

FJ is contained in plane R, BC and DE are contained in plane S, and FJ, BC, and DE intersect at A.

its hard for me

Nataliya D.

The problem says:
1. FJ is contained in plane R.
2. BC and DE are contained in plane S.
3. Point A is contained in plane R and in plane S.
Rest is 
- maybe ...
- might be ...
- could be ...
In other words, are not sufficient facts.



4 Answers By Expert Tutors


Stanton D. answered • 11/27/13

4.6 (42)

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Vladimir B. answered • 07/03/13

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Identify Hidden Active Causes. Imagine then Verify.

Rafael V.


Agree ......

In order for them to be perpendicular the vector normal to a plane must be parallel to the other plane

So either FJ have to be parallel to the normal vector at plane S

or ( BC or DE ) be parallel to the normal vector at plane R



Nataliya D. answered • 06/17/13

New to Wyzant

Patient and effective tutor for your most difficult subject.

Xavier J.

If we will know that FJ is perpendicular to BC or DE we will say that plane R | to plane S.

I'm not so sure we can automatically conclude that R and S are perpendicular if FJ were perpendicular.

Based off the info provided in the problem we have to assume FJ is on R and BC and DE are on S. This however does not mean BC, DE, or FJ cannot be the line of intersection of the 2 planes. Say we let DE be the line of intersection (DE will still be on the plane S) then the line FJ could be perpendicular to DE and R not be perpendicular to S.

The only way to ensure the 2 planes are perpendicular is to show that a line on either plane is perpendicular to the other plane.



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