Taylor H.

asked • 05/02/15# I have a graph of a hyperbola where the vertices are at (-3,0) and (3,0) and the center is (0,0). It needs to be written in a standard form

(x-h)

^{2 }/ a^{2}- (y-k)^{2 }/ b^{2}
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## 1 Expert Answer

center = (h,k) = (0,0)

vertices are (-a,0) and (a,0) = (-3,0) and (3,0)

a = 3

the hyperbola's equation is

(x-h)^2/a^2 - (y-k)^2/b^2 = 1

x^2/9 - y^2/b^2 = 1

or

(bx)^2 -(3y)^2 = 9b^2

asymptotes are y=bx/3 and -bx/3

foci are (-c,0) and (c,0) where c^2 = a^2 + b^2 = 9 + b^2, c = square root of (9+b^2)

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Mark M.

Since the center is (0, 0), h = k = 0. The distance from the center to either vertex is a. So, a = 3. To find b, we need further information. Did you leave something out?05/02/15