Nathan B. answered • 04/14/15

Tutor

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Elementary and Algebraic skilled

If the comet passes three more times, and it takes 57 years to make a single pass, then that means the equation we need is:

57 * 3 = 171

So it will take 171 years to complete three more passes.

If the last pass was 1965, then we add the time we just calculated to the original date:

1965 + 171 = 2136

So it will be 2136 after three more passes around the Sun.

If the comet loses 8000 m

^{3}every pass, and it passes three times, then the amount lost is the same as:8000 * 3 = 24,000

If the comet's mass in 1965 was 400,000 and it loses the 24k total after that third pass, then the equation looks like:

400,000 - 24,000 = 376,000.

And so the comet's mass will be 376,000 m

^{3}.