
Nathan B. answered 04/14/15
Tutor
5
(20)
Elementary and Algebraic skilled
If the comet passes three more times, and it takes 57 years to make a single pass, then that means the equation we need is:
57 * 3 = 171
So it will take 171 years to complete three more passes.
If the last pass was 1965, then we add the time we just calculated to the original date:
1965 + 171 = 2136
So it will be 2136 after three more passes around the Sun.
If the comet loses 8000 m3 every pass, and it passes three times, then the amount lost is the same as:
8000 * 3 = 24,000
If the comet's mass in 1965 was 400,000 and it loses the 24k total after that third pass, then the equation looks like:
400,000 - 24,000 = 376,000.
And so the comet's mass will be 376,000 m3.