To satisfy the System of Equations means that: if given two equations[2x + y > 0 ; -2x - y > -8], a set of values(Ordered Pair) will make it so that BOTH equations are true. So, you must plug each set of values, given as (x , y) into both the equations, and according to the question, only ONE set of the 4 given sets will make it so that the one or both of the equations are NOT true.
You have to plug in each set of values one at a time to figure out which one does NOT satisfy it;
Here is an example of plugging in one set of values(3 , -2).
(3 , -2) so, x = 3 ; y = -2
Now take the first equation[2x + y > 0] and plug in x = 3 ; y = -2
(2)*(3) + (-2) > 0
6 - 2 > 0
4 > 0 This statement is true. Now plug x = 3 ; y = -2 into the second equation[-2x - y > -8]
(-2)*(3) - (-2) > -8
-6 + 2 > -8
-4 > -8 This statement is also true. Therefore, since both equations are true with the plugged in values, we can say that the set of values(3 , -2) satisfies the system of equations, 2x + y > 0 and -2x - y > -8.
So, we continue on to the next set of values, and the next after that if they satisfy the system of equations.
ANSWER: The ordered pair (-1 , -1) does NOT satisfy the system of equations, as given by the following:
(x , y) = (-1 , -1)
(2)*(-1) + (-1) > 0 : -2 - 1 > 0
-3 > 0 is UNTRUE, and thus, fails to satisfy equation one of the system; if it fails to satisfy one of the two equations, then it fails to satisfy the system of equations.
BRUCE S.
Well done. I am just a brute force kinda guy on this one! ;-)
04/17/13