214 Answered Questions for the topic College Chemistry

If the temperature of argon gas is 400 K and the average velocity of argon is twice that of radon what is the temperature of radon gas?

The answer key says it is 555 K. How do I approach this question? 
College Chemistry Molarity

05/08/16

molarity question

after a student placed 20.0g of chromiu in 200ml of a H2SO4 solution she collected 2.8 L of H2 gas at 96.5 kPa and 25 C(Celsius). what was the concentration of the H2SO4  solution if she reported a... more
College Chemistry Chemistry Chemistry Lab

05/05/16

How many grams of [Co(NH3)5H2O]Cl3 will be produced?

2 CoCl2·6H2O + 2NH4Cl + 8NH3 + H2O2 --> 2 [Co(NH3)5H2O]Cl3 + 12 H2O   When 1.00 g of CoCl2·6H2O reacts with 0.7 g of NH4Cl, 3.0 mL of 15 M NH4OH and 3.0 mL of 10.% H2O2, how many grams of... more
College Chemistry

04/27/16

Determine the K, Equilibrium Constant

Determine the K(Equilibrium constant) for the salt NH4CN. 
College Chemistry

04/27/16

Writing a balanced net ionic equation 2

Write a balanced net ionic equation (no spectator ions) for the reaction that occurs when NaH2PO4 reacts with : a strong base = a strong acid =
College Chemistry

04/27/16

Writing a balanced chemical reaction

An aqueous solution of be2+ is slightly acidic. Write a balanced chemical reaction that shows why. (Note: Be2+ is surrounded by four water molecules when it is in solution)
College Chemistry

04/27/16

Determine the K salt

Determine the K salt for the salt NH4CN.
College Chemistry

04/27/16

finding the conjugate base and acid of salts

State a reasonable salt that would be a conjugate for the acid or base listed below. The counter ion should be neutral. Quinoline,C9H7N                 conjugate : HPO4^2-                  ... more
College Chemistry

04/26/16

What is the molecular formula of SxFy ?

General formula : SxFy One of the compound is 25.23%S. If you place 0.0955 of the compound in a 89 mL flask at 45 degree celcius, the pressure of the gas is 83.8mmHg. What is the molecular formula ?
College Chemistry Chemistry General Chemistry

04/12/16

Using a Manometer to Measure Gas Pressure PROBLEM

If the gas inside the flask in the above exercise is cooled so that its pressure is reduced to a value of 715.7 torr what will be the height of the mercury in the open-end arm? (Hint: The sum of... more
College Chemistry

04/06/16

How can I find the pH of a solution of NaHCO3?

Is there a way to find pH of such partially neutralised poly basic weak acid solutions which act both as an acid and base? Also how can I find the pH of NH4Ac solution? Is it possible to derive the... more
College Chemistry Chemistry General Chemistry

03/29/16

Lewis Structure problem

I AM SO CONFUSED WITH THIS ONE CHOICES ARE 3,4,5,6,7   Phosphorus oxychloride has the chemical formula POCl3, with P as the central atom. In order to minimize formal charge, how many bonds does... more
College Chemistry

03/25/16

Chemistry Finding the unknown concentration of the unknown solution?

a 33.00 mL sample of an H2SO4 solution of unknown concentration is titrated with a 0.1222 M KOH solution A volume of 40.22 mL of KOH was required to reach the equivalence point.   What is the... more
College Chemistry Stoichiometry

03/23/16

How many moles of O2 are needed to oxidize 6.71 moles of CuFeS2 in the reaction 2 CuFeS2 + 5 O2 ———> 2 Cu + 2 FeO + 4 SO2

I really don't know how to do it I've tired and tried. I know how to balance, I have consistantly practiced but am getting no where. How many moles of O2 are needed to oxidize 6.71 moles of CuFeS2... more
College Chemistry

03/23/16

How many moles of NaCl are needed if we want to make 4.37 moles of AgCl by the reaction 3Fe2O3 + 3O -> 2Fe3 + 3CO2

How many moles of NaCl are needed if we want to make 4.37 moles of AgCl by the reaction 3Fe2O3 + 3O -> 2Fe3 + 3CO2
College Chemistry

03/22/16

How many milliliters of an aqueous solution of 0.167 M potassium nitrate is needed to obtain 12.0 grams of the salt?

college chemistry
College Chemistry

03/22/16

If 0.528 mole of Al2S3 react with 3.70 mole HCl, how mant grams of H2S are formed

If 0.528 mole of Al2S3 react with 3.70 mole HCl, how mant grams of H2S are formed
College Chemistry

03/15/16

Calculate the mass of KHP needed to react completely with 25 mL of a 0.10 M NaOH solution. Consider the reaction equation to be as shown below.

 NOTE: The “P” in KHP ( 204 g/mol ) is an abbreviation for “phthalate”. It is not the element phosphorus. Calculate the mass of KHP needed to react completely with 25 mL of a 0.10 M NaOH solution.... more
College Chemistry Chemistry General Chemistry

03/09/16

PLEASE HELP ME WITH CHEM TITRATION PROBLEM??!!!

A 25.0 mL sample of 0.150 M hypochlorous acid is titrated with a 0.150 M NaOH solution. What is the pH after 26.0 mL of base is added? The Ka of hypochlorous acid is 3.0 × 10-8.   7.51 11.47 7.54... more

03/09/16

Buffer/Titration Chemistry Problem??! PLEASE HELP - I AM LOST!!!

A 25.0 mL sample of 0.723 M HClO4 is titrated with a 0.273 M KOH solution. The H3O+ concentration after the addition of 66.2 mL of KOH is __________ M. 0.723 1.00 × 10-7 2.81 × 10-13 0.439... more

03/09/16

CHEM 2 Solubility Equilibrium Question?? PLEASE HELP!?

Hi everyone. I have two questions that I think I found the answer to, but could you check and see if they are right? If they are incorrect, could you show me how you achieved the correct answer?... more
College Chemistry Chemistry Ap Chemistry Equilibrium

02/21/16

Equilibrium Constant

The basic question I am asking is how does varying the initial concentrations of reactant(s) in a chemical reaction affect the equilibrium constant. What I have so far is:   Using this basic... more
College Chemistry Chemistry General Chemistry

02/19/16

You carefully weigh out 17.00 g of CaCO3 powder and add it to 68.85 g of HCl solution. You notice bubbles as a reaction takes place. (contnd at description)

Question:You carefully weigh out 17.00 g of CaCO3 powder and add it to 68.85 g of HCl solution. You notice bubbles as a reaction takes place. You then weigh the resulting solution and find that it... more

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