
Mitchell S. answered 03/26/16
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This is a strong-acid strong-base titration. The general reaction is:
acid + base = salt + water
Therefore the balanced reaction is:
H2SO4 + 2KOH --> K2SO4 + 2H2O
We see that 2 moles of KOH is required to neutralize 1 mole of H2SO4
40.22 mL KOH * 0.1222 mol/L * 1L/1000mL = 0.0049 moles of KOH
Using the mole-to-mole ratio of the reaction:
0.0049 mol KOH * 1 mol H2SO4/2 mol KOH= 0.00245 moles H2SO4 used in the reaction
Since we know that 33mL of H2SO4 was present originally, the concentration is just:
0.00245 mol H2SO4/33mL * 1000mL/L = 0.074 M H2SO4