(2z-2)(z+3)=0

Question

Solve the equation!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Answer 1

Hello, thank you for taking the time to post your question!

When you have an expression that has already been factored like this you can just set each part equal to 0 in order to solve. On this one that means

2z - 2 = 0   ==>     z = 1

z + 3 = 0 ==>      z = -3

I hope that helps you get moving in a better direction on this type of question! Feel free to reach out if you have any additional questions beyond that :)

Answer 2

There are probably a couple of ways to do this, but I chose multiplying it out in polynomial form to start with.

(2z-2)(z+3)=0 ( I think it's the distributive law(I know it's one of the laws...) for the multiplication that's done, to make it a polynomial.)

2z(z) +(2z(3)) -2z-6=0

(^2, this ^denotes raised to the power of, in this case 2, so z^2 is z squared)

2z^2+6z-2z+6=0 simplify

2z^2+4z-6=0

z^2+2z-3=0

(z+3)(z-1)=0 now from here it's in a more familiar and in an easier form to resolve

z+3=0 and z-1=0

z+3=0

z= -3

now we solve for

z-1=0

z=1