I need step by step instructrions on how to complete this problem.
((x^-3y^4z^-2)^2)/y^0z^-2
I need step by step instructrions on how to complete this problem.
((x^-3y^4z^-2)^2)/y^0z^-2
Hello Nyeirah. Here is how I read your problem:
((x^-3y^4z^-2)^2)/y^0z^-2 = ((x^{-3}y^{4}z^{-2})^{2})/y^{0}z^{-2}
If that is a correct restatment of the problem, then the following is how I would solve it. (NOTE: my answer might differ from other tutor's answers because we read the problem you wrote differently. I am answering what I think you are asking.)
First, we need to get rid of some of those parentheses in the numerator. Recall that (A^{m})^{n} =A^{mn} .
((x^{-3}y^{4}z^{-2})^{2})/y^{0}z^{-2}
= x^{-6}y^{8}z^{-4}/y^{0}z^{-2}
Now for the denomiator, y^{0} is just 1. Anything to the zero power is just 1.
=x^{-6}y^{8}z^{-4}/z^{-2}
When the only operations between terms are multiplication and division, like we have here, then you can move terms from denominator to numerator by changing the sign of the exponent. We will move the z^{-2} term to the numerator and change its exponent from -2 to 2.
=x^{-6}y^{8}z^{-4}z^{2}
Now combine those two z terms. The rule is A^{m}A^{n}=A^{m+n}. Here z^{-4}z^{2
}= z^{-4+2 }= z^{-2}
x^{-6}y^{8}z^{-2} [Answer]
We can rearrange if we like to put all the negative exponent terms in the denominator.
y^{8}/x^{6}z^{2} [Answer, in a different form]
Let's look at this in two parts: Numerator and Denominator
Demoninator first b/c its easy
0*z=0
0^{-2}=0
Therefore y^{0}=1 because any number taken to the power 0 is equal to 1
So your denominator is 1
Numerator:
Let's start inside the parenthese to see what we can simplify. Starting at the highest exponent 4z^{-2}
4z^{-2}=1/(4z^{2})
x^{-3y} = 1/(x^{3y})
so you are left with (1/(x^3y^(1/4z^{2})))^{2}=(1/(x^6y^(1/4z^{2}))) since when you square an exponential function you mutiply the square (or 2) by the exponent
Comments
A bit late and not related to the original question, but shouldn't the 0^{-2} in your response be undefined, not equal to zero? As it'd be equivalent to 1/0^{2}.
No. 0^{-2} = 1/(0*0). Since 0^{-2} is in the denominator it actually 1/0^{-2} = 0*0^{ }
Sorry i took another look at my original response. Let me clarify that the 0 is an exponent and how I read the problem was that the whole exponent was 0*z^{-2}. So actually I did make a mistake Good catch. I should have just written that 0*z^{-2} = 0 not 0^{-2}. So while followed that throughout the proble I should not have written 0^{-2}.