Cagri T. answered 04/03/26
5+ years private tutoring to elementary and middle school students.
If you know how to calculate the surface area of a cylinder, the only tricky thing about this question is to calculate the area of the two (identical) triangles and to subtract it from the area of the cylinder.
Let's first calculate the surface area of the cylinder, which has two components:
1 - The curved surface: 2 x (pi) x r x h
2 - The area of two circles: 2 x (pi) x r x r
where r is the radius of the circle, h is the height of the cylinder and pi = 3.14. r = 12/2 = 6 and h = 45
So we get:
For 1: 2 x (3.14) x 6 x 45 = 1695.6
For 2: 2 x (3.14) x 6 x 6 = 226.08
Area of the cylinder (S) = 1695.6 + 226.08 = 1921.68
Now let's take a look at the triangles that are cut out from the two circular faces of the cylinder.
The triangles are isosceles. Therefore, the height of each triangle divides the base into two equal parts. Also , each half of a triangle is a right triangle, and therefore we can calculate the height using the Pythagoras theorem as follows:
Hypotenuse = 5
Opposite side = 4
Adjacent side (h) = ?
5 x 5 = (4 x 4) + (h x h)
h = sqrt(9) = 3
Base of each triangle is given and is 8 so the area of one of the triangles (A) is then A = 1/2 x 8 x 3 = 12
Since there are 2 identical triangle cut outs we need to calculate 2 x A which is 2 x 12 = 24
Finally, we get the answer by S - 2A = 1921.68 -24 = 1897.68
I enjoyed solving this question :)
William W.
You mention removing 12.5 square units from the top and bottom. Shouldn't this be 12? The height of the triangle would be 3 (the median splits the base of 8 in half creating a 3-4-5 right triangle). A = (1/2)(8)(3) = 1207/28/25