Find the area of the figure

Question

https://ibb.co/Z1JG6TmB

Answer 1

You do not have any height measurement on the right-most rectangle. Therefore, it's area cannot be found. Also, I cannot read the height on the rectangle with a base of 5 cm, but I'll use 7 cm, since it's the height of the piece adjacent to it. Also, although I should never do this, I am going to assume right angles.

However, the others can:

1. Square on left: A=s², so A=7²=49 cm²
2. Triangle 1 (below the square): A=1/2 bh, so A=1/2(7)(4)=14 cm²
3. Rectangle 1 (adjacent to square): A = bh, so A = (15)(7) = 105 cm²
4. Triangle 2 (above rectangle): A=1/2 bh, so A=1/2(15)(6)=45 cm²
5. Rectangle 2 (to the right of Rectangle 1): A = bh, so A = (5)(7) = 35 cm²
6. Rectangle 3 (to the right of Rectangle 2): A = bh, so A = (3)(?)

For the total area, just add all the component areas together.

Answer 2

There is not enough information here to solve the problem without making some assumptions:

Assumption 1: The triangles are isosceles.

Assumption 2: The right side rectangle sticks up 3 cm on the lower and upper ends.

Just break this shape into 4 rectangles and 2 triangles. Use the Pythagorean Theorem to find the hypotenuse (which is the slant length).

A_triangle = (1/2)(b)(h)

A_rectangle = (L)(W)