Raymond B. answered 06/21/25
Math, microeconomics or criminal justice
60-30-30 m for sides
area = 60(30) = 1800 m^2
area = sL
120 = L +2s
L = 120-2s
area = s(120-2s) = 120s -2s^2
A' = 120 -4s = 0
4s = 120
s = 120/4 = 30
L = 120-2(30) = 60
Loinse B.
asked 05/28/25A landscaper has 120 meters of fencing and wants to enclose a rectangular garden next to a straight pond, using the pond as one of the longer sides of the rectangle. Fencing is only required for the remaining three sides (the two short sides and the side opposite the pond).
What dimensions will maximize the enclosed area? Additionally, what is the maximum area that can be enclosed?
Raymond B. answered 06/21/25
Math, microeconomics or criminal justice
60-30-30 m for sides
area = 60(30) = 1800 m^2
area = sL
120 = L +2s
L = 120-2s
area = s(120-2s) = 120s -2s^2
A' = 120 -4s = 0
4s = 120
s = 120/4 = 30
L = 120-2(30) = 60
Get a free answer to a quick problem.
Most questions answered within 4 hours.
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.