
Doug C. answered 04/26/25
Math Tutor with Reputation to make difficult concepts understandable
Let x = #apples she started with. That means she arrives at Door 1 with x apples.
x -> Door 1: -> (1/2)x she leaves with
(1/2)x -> Door 2: -> (1/4)x she leaves the guard 1/2 of what she started with so has 1/2 of those apples in her basket.
(1/4)x -> Door 3: -> (1/8)x (this is 1/2 of what she came to the door with)
(1/8)x -> Door 4: -> (1/16)x -- finally this is what remains
But we know she remained with 10 apples so:
(1/16)x = 10
x = 160; the woman started with 160 apples
This is actually an exponential decay problem with base (1/2).
A = initial(1/2)t
We know that A = 10, when t = 4:
10 = x(1/2)4
(1/16)x = 10
x = 160
So the exponential decay function is:
A(t) = 160(1/2)t, where t is number of doors she has gone through.
A(0) = 160
A(1) = 80
A(2) = 40
A(3) = 20
A(4) = 10