Mike M. answered 03/28/25
Math Tutor specializing in Algebra, Pre-Calculus, Trig, and Calculus
When I do these type of problems, my strategy or what I wanna think about is
Number one. Recognize that you have two equations with two unknowns. In this case, x and y
Number two. Either add the two equations together or subtract one equation from the other to get a result of having just X or Y remaining.
Number three. To do either the subtraction method or the addition method mentioned above, you may have to multiply through or divide through on one of the equations to get to an equivalent equation that is easy to subtract or add from the other equation to eliminate one of the variables.
In this case, both equations have a 2Y so we can just do equation one minus equation 2 and eliminate the Y variable.
X plus 2Y equals 7
Minus. 2X plus 2Y equals 13.
Equals. Negative X plus 0Y equals -6.
Solving for X you get X equals 6
Number four. After solving for one of the variables, we can then substitute the variable we just solve for and substitute back into one of the original equations and solve for the other variable.
So substituting X equals 6 into the first equation and solving for Y
6+ 2Y equals 7
Subtracting six from both sides 2Y equals 1 remains
Then solving for y by dividing by two on each side, we get Y equals 1/2
In summary. Two unknown variables. Add or subtract the two equations to get one unknown remaining. Solve for a solution. For the other unknown.
as an alternative to above, we could have multiplied the first equation by -2, and then added that equation to the second equation to eliminate X and just have y variable remaining and then solve for y and been done
-2x - 4y = -14
plus. 2x + 2y = 13
Equals. 0 -2y = -1
solving for y. Y = 1/2