Jane M.

asked • 04/02/15

the graph of f passes through (-1,5) and is perpendicular to the line whose equation is x = 6.

I am really not sure how you solve this slope intercept form of liner function.

Vamos P.

Here is how I solved it. Use the formula for slope-intercept form: y - y1 = m(x - x1)

First, write x = 6 into the general form of the line: Ax + By + C = 0

So, (x = 6) becomes (6)x - (-1/5)y - 0 = 0 (Use -1/5 instead of 5 because the line is perpendicular and perpendicular means the NEGATIVE RECIPROCAL of the line)

 

Next, y - y1 = m(x - x1)

y - 5 = -1/5[x - (-1)]

y - 5 = -1/5(x + 1)

y - 5 = -1/5x + 1/5

   +5 =           + 5

     y = -1/5x + 25/5

     y = -1/5x + 5

      y = 5 or f(x) = 5

 

 

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06/19/16

2 Answers By Expert Tutors

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Michael J. answered • 04/03/15

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x = 6 is a vertical line because no matter what y value you have, the x value remains 6.
 
Points of x=6 are (6,0), (6,1), (6,2), (6,3) and so on.
 
A line perpendicular to that is  y = b, which is a horizontal line because the slope of a horizontal line is zero.
 
y = b passes through the point (-1,5). Since the y value of this point is 5, the equation of the line is
 
y = 5
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