The sum of three prime numbers is 100.one of them exceeds the other by 24.what are the three no, s.

Answer 1

2, 37 and 61

they sum to 100

and 61=37+24

all 3 are prime

a+b+c = 100

c=b+24

a+b+b+24 = 100

2b = 76 -a

b = 38 -a/2 so a must be even and there is only one even prime, so a=2

b = 38-1 =37

c = 37+24 = 61

2,37 and 61 have no positive integer factors other than 1 and itself

Answer 2

x + y + z = 100

z = y + 24

So:

x + y + y + 24 = 100

x + 2y = 76

2y = 76 - x

y = 38 - (1/2)x

That means x = 2 (the only prime number that is evenly divisible by 2)

If x = 2, then y = 38 - 1 = 37.

And z = 37 + 24 = 61.

Three prime numbers that add to 100 are:

2, 37, 61.