- 2x = f(x)
- if x = 1, then f(x) = 2
- if x = 2, then f(x) = 4
(2x - 2) (2x - 4) = 0
= 22x - 6 * 2x + 8 = 0, subtract 12 on both sides of the equation
= 22x - 6 * 2x - 4 = -12
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f (x) = Log2 (x)
- if x = 1, f(x) = 0
- if x = 2, f (x) = 1
Log2 (x) (Log2 (x) - 1) = 0
= (Log2 (x))2 - Log2 (x) = 0, subtract both sides of the equation by 12
= (Log2 (x))2 - Log2 (x) -12 = -12
You do not need to use 12, you can use many different values except for those with 3's.