Probability = favorable outcomes / all possible outcomes.
In this case, there are six possible outcomes (1 to 6), none of which is favorable outcome, a 7.
Probability = 0 / 6 = 0.
Answer: Probability of getting a 7 is 0.
Jordynn L.
asked 02/20/25When a normal six-sided die is rolled, what is the probability of getting a 7?
Probability = favorable outcomes / all possible outcomes.
In this case, there are six possible outcomes (1 to 6), none of which is favorable outcome, a 7.
Probability = 0 / 6 = 0.
Answer: Probability of getting a 7 is 0.
Hello Jordynn,
I think you might have been given an assignment with a bit of a trick question haha, the idea of a “normal” die is that there were would be 6 sides, each representing the digits from 1 to 6. What that means is that the probability of getting a 7 is actually 0/6 = 0.
It’s not possible to roll a 7 on a normal die, in other words :)
Feel free to message me to set up a lesson if you have any other questions!
Inactive Tutor answered 02/20/25
A six-sided die contains the numbers 1 through 6, one on each face. It is impossible to roll a 7. That means the probability is 0.
It would be a different story if there were two dice rolled. Then you could get a 7 with several different combinations:
6-1
1-6
5-2
2-5
4-3
3-4
A total of 6 outcomes that result in a roll of 7.
There are 36 possible outcomes when you roll two dice (6 times 6).
So the probability of rolling a 7 with two dice is 6 out of 36 (6/36 or 1/6).
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