write an equation for a quadratic function that has zeros (6,0) and (-4,0) and the parabola passes through the point (0,8)

Answer 1

Hi Grant H

Since you are given the zeros you can set up your quadratic first in factored form, then use your given y intercept to find the value for a and finally write the equation

Given zeros (6,0) and (-4,0)

y = a(x -6)(x + 4)

Now use the given y intercept to find a (0,8)

8 = a(0 - 6)(0 + 4)

8 = a(-6)(4)

8 = -24a

Just solve for a

a = -1/3

In factored form you have the following quadratic equation

y = -1/3(x - 6)(x + 4)

If you multiply this out you can the general form

y = -1/3(x² - 2x -24)

You can graph your quadratic equation to check and see that it passes through the points given.

I hope this helps

Answer 2

See the videa.