write an equation for a quadratic that has a vertex of (-1,-3) and passes through the point (2,4)

Answer 1

See the videa.

Answer 2

y = a(x + 1)² - 3; 4 = a(2 + 1)² - 3; 7 = 9a; a = 7/9; y = 7/9(x + 1)² - 3;

Answer 3

You can use the generic equation for a quadratic:

where the point (h, k) is the vertex, So plug in h = -1 and k = -3 to get:

y = a(x - -1)² + -3 or

y = a(x +1)² - 3

To find the value of "a", plug in the point (2, 4) for an (x, y)