7.) The length of a rectangle is 5 less than 2 times the width. Write the equation that represents this situation. Then find the L and W if the perimeter is 38 centimeters. 36= 2(L*4) 38=2（24-351）

Answer 1

Lenth = l, Width = w

l = 2w - 5

P (perimeter) = 2l + 2w = 38

By substitution, 2(2w-5) +2w = 38 => 4w -10 +2w = 38

6w - 10 = 38 => 6w = 48 => w = 8

l = 2w - 5 = 2 * 8 - 5 = 11

So lendth is 11 cm, width is 8 cm

Answer 2

See the videa.