math question please help

Question

Find the area of the region that lies inside the first curve and outside the second curve, 𝑟 = 3 sin 𝜃 , 𝑟 = 1 + sin 𝜃.

Answer 1

desmos.com/calculator/mq7m8yrx3i

Answer 2

3sinθ = 1 + sinθ; sinθ = 1/2; θ = π/6 or θ = 5π/6

Area A = 1/2∫_π/6^5π/6(9sin²θ - (1 + sinθ)²)dθ = 1/2∫_π/6^5π/6(3 - 4cos2θ - 2sinθ)dθ = 1/2(3θ - 2sin2θ + 2cosθ)_π/6^5π/6 = 1/2(2π - 2sin5π/3 + 2cos5π/6 + 2sinπ/3 - 2cosπ/6) = π + √3/2 - √3/2 + √3/2 - √3/2 = π