
Mark M. answered 11/02/24
Mathematics Teacher - NCLB Highly Qualified
Draw and label a diagram!
BC = 6b - 4a
CD = -4b + 2a
BD = 3b - 2a
Use Segment Addition Property to complete.
Chance P.
asked 11/02/24If A, B, C, D are four points such that
(AB) ̅= 2A,
(AC) ̅= 6b -2a,
(AD) ̅= 3b,
how can you prove that B,C,and D are collinear?
Mark M. answered 11/02/24
Mathematics Teacher - NCLB Highly Qualified
Draw and label a diagram!
BC = 6b - 4a
CD = -4b + 2a
BD = 3b - 2a
Use Segment Addition Property to complete.
Potcharapol S. answered 11/03/24
One way to show that three points are collinear is to show that any two segments are parallel. In this case, if you can show that BC and BD are parallel, it follows that B,C,D are collinear. To that end, we need to show that BC = kBD for some constant k.
BC = AC-AB = (6b-2a)-(2a) = 6b-4a
BD = AD-AB = (3b)-(2a) = 3b-2a
So, BC = 6b-4a = 2(2b-2a) = 2BD as desired.
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Bradford T.
CD =AD-AB-BC=3b-2a-6b+4a=-3b+2a11/02/24