3(x-4) = 2(x+6)+4
3x - 12 = 2x + 12 + 4
3x - 2x = 12 + 12 + 4
x = 28
This question invites students to apply their skills in solving linear equations. It challenges them to distribute, combine like terms, and isolate the variable. Solving this equation will reinforce their understanding of algebraic manipulation and problem-solving techniques. Additionally, it opens the door for further discussion about the importance of equations in real-life situations, such as budgeting or calculating distances, making the topic more relatable and interesting for students!
3(x-4) = 2(x+6)+4
3x - 12 = 2x + 12 + 4
3x - 2x = 12 + 12 + 4
x = 28
FREDRICK K. answered 10/31/24
special needs education teacher with broad knowledge on math
3(x−4)=3x−12
2(x+6)+4=2x+12+4=2x+16
3x−12=2x+16
3x−2x−12=16
x=16+12
x=28
28
3(x - 4) = 2(x + 6) + 4
3x - 12 = 2(x+6)+4
3x - 12 = 2x + 12 + 4
3x - 12 = 2x + 16
Add 12 to both sides to bring all of the constants to the right.
3x = 2x + 16 + 12
3x = 2x + 28
Subtract 2x from both sides to bring all of the variables to the left.
3x - 2x = 28
x = 28
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FREDRICK K.
Check when you were distributing the second parentheses you have 2x+12+4 and not 2x+2+411/03/24