Let x = number of years from 2020 that it takes for the colleges to have the same enrollment
15800 + 500x = 33800 - 1000x
1500x = 18000
x = 180/15 = 12 years
The colleges will have the same enrollment in the year 2032.
Miranda H.
asked 10/30/24In 2020, there were 15,800 students at college A, with a projected enrollment increase of 500 students per year. In the same year, there were 33,800 students at college B, with a projected enrollment decline of 1000 students per year. According to these projections, when will the colleges have the same enrollment? What will be the enrollment in each college at that time?
Let x = number of years from 2020 that it takes for the colleges to have the same enrollment
15800 + 500x = 33800 - 1000x
1500x = 18000
x = 180/15 = 12 years
The colleges will have the same enrollment in the year 2032.
Karen W. answered 10/31/24
Karen, B.S. in Math, Wyzant Certified Tutor in Many Subjects
I agree with Mark M’s solution. The colleges will have the same enrollment in the year 2032. The question also asks what the enrollment in each college will be at that time.
To find that answer, plug 12 (years) into the original equation.
15,800 + 500x = 33,800 - 1,000x
15,800 + 500*12 = 33,800 - 1,000*12
15,800 + 6,000 = 33,800 -12,000
21,800 = 21,800
So we can see that each college will have an enrollment of 21,800 students in the year 2032.
Get a free answer to a quick problem.
Most questions answered within 4 hours.
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.