J(x)=4/5x + 7 ; j(x) =-5

Answer 1

I'm making the assumption (a) that J(x) and j(x) are equivalent and that (b) the implied question is solve for x.

Otherwise, you would need to provide more information.

-5 = 4/5x + 7 [Set the two expressions equal to each other]

-12 = 4/5x [Subtract 7 from both sides]

x = -15 [Multiply both sides by 5/4 (reciprocal of 4/5)]

Answer 2

I'm assuming you want to solve for x.

If we're given J(x) = (4/5)x + 7 and J(x) = -5, we want to find x when J(x) = -5. We can set up the following algebraic equation and proceed to solve:

J(x) = -5

(4/5)x + 7 = -5

(4/5)x = -12 [Subtract 7 from both sides]

x = -12 * (5/4) [Multiply both sides by 5/4, the reciprocal of 4/5]

x = -15

We can check our work; plug x = 15 into J(x) and see if you get -5:

(4/5) * (-15) + 7

-12 + 7

-5

We get -5, so x = -15 is confirmed to be the correct answer.

Hope this was helpful.