Melanie F.
asked • 10/11/24calculus math; derivatives
2xy +y^2 +sinx find dy/dx
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1 Expert Answer
Dayv O. answered • 10/11/24
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Caring Super Enthusiastic Knowledgeable Pre-Calculus Tutor
If 2xy +y^2 +sinx =constant
need to us implicit differentiation and chain rule
[2y(dx/dx)+2x(dy/dx)]+[2y(dy/dx)]+{(cos(x))(dx/dx)]
dy/dx=-(cos(x)+2x)/2y
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Dayv O.
hi Melanie,, is 2xy +y^2 +sinx =f(x,y): then the equation is a surface. If 2xy +y^2 +sinx =constant: then equation is a curve in xy plane. Can you clarify?10/11/24