Verbal Domain&Range

Question

Luis charges a travel fee of $10 plus $25 per month to mow his neighbors' lawns. The equation y = 25x +10 can be used to determine the travel fee for x months. If most of his customers only get their lawns mowed for 5 to 8 months out of the year, what is the range of this situation?

Answer 1

Hi Lajaveon W,

According to the equation you provided,

the lowest range would be y=25(5)+10 = $135

and the highest range would be y=25(8)+10 = $210.

And the range would be 210-135 = 75

However, since Luis charges a travel fee of $10 in addition to $25 of lawn service, I believe the equation should be y = (10+25)x since he would have to travel to his customer place every single time he have to mow their lawn.

In this case, the lowest range would be y = 35*5 = $175

and the highest range would be y = 35*8 = $280

So, the range for this situation is 280-175 = 105

Answer 2

Hi Lajaveon W.

First of all, it's very important to read well the questions and understand what is been asking.

1st. Each travel fee is $10.00

2nd. An additional amount of $25.00 is charged for each lawn service.

That means that each service is: $10+$25=35.00

3rd. customers only get their lawns mowed for 5 to 8 months out of the year. So, there is a variable in how many times the service is required by the customers. Using x as the variable of service required the expression to use must be:

y=(10+25)x; y=35x

The lowest range is y=35.00*5=175.00

The highest range is y=35.00*8=280.00

Finally, we can write this way: 175<=y<=280 as the range of that situation.

Answer 3

Plug in 5 for x in the equation to get 25*5 + 10 = $135 as the lower end of the range.

Plug in 8 for x in the equation to get 25*8 + 10 = $210 as the higher end of the range.