(-7​,-5​); y=- 5 x + 1 i need help putting this into slope intercept

Answer 1

The other one has two errors.

1. slope is -5, NOT -7
2. We are finding Slope - intercept form => y = mx + b

So, let's redo it here~

(-7​,-5​); y=- 5 x + 1

I assume that a linear function is parallel to y = -5x + 1 and going through (-7, -5).

Then, m = -5.

y = -5x + b => substitute (-7,-5) into equation, then

-5 = -5 * (-7) + b => -5 = 35 + b => -40 = b

so, b = -40 and m = -5

y = -5x - 40

Answer 2

In the slope-intercept form of a linear equation,

y = m x + b

m is the slope and b is the y-intercept.

The point-slope form looks like this:

y - y₁ = m ( x - x₁ )

where ( x₁ , y₁ ) is a given point and m is the slope.

We were given the slope from the other equation, so we know it is -5. The point given is ( -7 , -5 ). Let's just plug these values into the point-slope generic equation:

y - ( -5 ) = ( -5 ) * ( x - ( - 7 ) )

Simplifying:

y + 5 = -5 ( x + 7 ) *

Using the distributive law:

y + 5 = -5x -35

Subtracting 5 from both sides:

y = -5x -40 *

If you graph both starred (*) equations using the Desmos online graphing calculator, you will see they define exactly the same line.

Note: the slope-intercept form is just a simplified version of the point-slope equation using the y-intercept point ( 0 , b ), or ( 0 , 1 ) in this case at the top of the page, and ( 0 , -40 ) as the other equation.

I presume the problem should have stated "find a line parallel to y = -5x + 1 which goes through the point

( -7 , -5 )." Parallel lines have the same slope.