Help me on this question please.

Question

Felipe made 6 identical necklaces, each having beads and a pendant. The total cost of the beads and pendants for all 6 necklaces was $38.40. If the beads cost $2.70 for each necklace, how much did each pendant cost?

Answer 1

We have two unknowns in this problem.

Let b be the cost of the beads on a single necklace

Let p be the cost of the pendant on a single necklace.

Then the total cost comes out to be the cost of the beads on the six necklaces plus the cost of the pendants on the six necklaces.

Because we have 6 groups of beads and 6 pendants, we get the equation:

6b + 6p = $38.40

We're given b = $2.70

By substituting

6($2.70) + 6p = $38.40.

Lastly solve for p

Answer 2

$2.70 per necklace for beads

For 6 necklaces that is 6($2.70) or $16.20

Beads + 6 pendants = $38.40

$16.20 + 6 pendants = $38.40

Can you solve for pendant and answer?