College algebra

Question

Find the equation of the circle that satisfies the given conditions. Center (0,2/3), and radius √15

Answer 1

Hello, thank you for taking the time to post your question!

The standard from of the equation of a circle is

(x – h)^2 + (y – k)^2 = r^2, where

(h, k) is the center of the circle

r is the radius

for the values given in this question that becomes

(x – 0)^2 + (y – 2/3)^2 = (sqrt(15))^2, which simplifies down to

x^2 + (y – 2/3)^2 = 15

I hope that helps you get moving in a better direction on this type of question! Feel free to reach out if you have any additional questions beyond that :)

Answer 2

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