Help with math homework

Question

Suppose Q is the midpoint of PR. Use the information to find the missing value.

PQ=6x+25 and QR=16−3x ; Find the value of x and PR .

Answer 1

PR has a midpoint of Q.

So, PQ=QR

Now, substitute

6x+25=16-3x

(add 3x to both sides)

9x+25=16

(subtract 25 from both sides)

9x=-9

(divide both sides by 9)

x=-1

Now substitute x back into PQ and QR

PQ = 6x+25 = 6(-1)+25 = -6+25 = 19

QR= 16-3x = 16-3(-1) = 16+3 = 19

PR = PQ + QR = 19+19 = 38

PR = 38

Answer 2

We will set PQ=QR to solve for x.

6x+25=16-3x

-25 -25 ----Subtract 25 to right side

6x=-9-3x

+3x +3x -----Next add 3x to the left side

9x=-9

/9 /9 ----Final step to solve for x divide both by 9

x=-1 then substitute -1 into equal for PR=6x+25

PR=6(-1)+25=-6+25=19 for the length of PR

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