math calc help please

Question

integral x-3/x^2+1dx

Answer 1

∫ [(x - 3) / (x²+1)]dx = ∫ [ x / (x²+1)]dx - 3∫[1 / (x²+1)]dx

For the first integral, let u = x²+1. So, du = 2xdx. Therefore, xdx = (1/2)du.

So, we have (1/2)∫ (1/u)du - 3Arctanx = (1/2) ln(x²+1) - 3Arctanx + C

Answer 2

∫(x+3/x²+1)dx = x²/2-3/+=x+Constant