How to translate each rule into a formula

Question

The distance d in feet and object falls is equal to the product of 16 and the square of the time t in seconds

Answer 1

Hi Kalya,

The object falls with a constant acceleration g

If it falls from test, the distance d from its starting point changes with time as d=g t^2/2 where g is the acceleration of free fall

If distance is measured in feet g=32ft/s^2

Therefore d=gt^2/232 t^2/2=16t^2 where d is in feet , t in seconds

Hope that'd help

Best,

Dr.Boroda

Answer 2

d = 16t²