Mathisprettynice

Question

the length of a rectangle is 5 inches more than its width. if the perimeter of the rectangle is 38 inches, what are the dimensions of the rectangle?

Answer 1

Let x = width. Then length = x + 5

So, 2x + 2(x+5) = 38

4x + 10 = 38

4x = 28

x = 7

The width is inches and the length is 12 inches.

Answer 2

Let length = L and width = w

L = w + 5

Perimeter = 2L + 2W

2l + 2w = 38

Substitute L with w expression in order to solve for w:

2(w + 5) + 2w = 38

2w + 10 + 2w = 38

Combine like terms:

4w + 10 = 38

4w = 28

W = 7

Plug back in to find L:

L = 7 + 5

L = 12

Answer 3

I have solved this word problem in this video. Check it out and let me know if you have any additional questions. I hope you find this helpful. Take care

Dr. Christal-Joy Turner

Answer 4

Perimeter = all the sides added together

Let x = the width

x+5 = length (the length is 5 inches more than the width)

38 = x+x+(x+5)+(x+5) Now will solve combine like terms

38=4x+10 Subtract 10 from both sides

38-10=4x+10-10 Simplify

28=4x Divide both sides by 4

28/4=4x/4

x=7

x+5=7+5=12

The width is 5 inches, the length is 12 inches