evaluate h(4-n) given that h(t)=20-t

Answer 1

you're given that h(t) = 20 - t for the original function

to find h(4 - n) then you want to plug in t = 4 - n into h(t)

h(4 - n) = 20 - (4 - n)

=20 - 4 + n

=16 + n

Answer 2

To evaluate h(4−n) given that h(t)=20−t, we'll follow these steps:

Step 1: Understand the Function

The function provided is h(t)=20−t. This means that for any input t, the function will subtract t from 20.

Step 2: Substitute 4−n4-n4−n for t

We need to find the value of h(4−n). To do this, we substitute 4−n in place of t in the function h(t)=20−t.

So,

h(4−n)=20−(4−n)

Step 3: Simplify the Expression

Next, we'll simplify the expression inside the parentheses.

The expression 20−(4−n) can be rewritten as:

h(4−n)=20−4+n

Here’s how we arrived at this:

1. Distribute the negative sign across the expression inside the parentheses: −(4−n) becomes −4+n.
2. Now, subtract 4 from 20, and you get:

h(4−n)=16+n

Final Answer

So, the final simplified expression for h(4−n) is:

h(4−n)=16+n

This means that if you input 4−n into the function h(t), the output will be 16+n

Answer 3

When doing these kinds of problems, you want to substitute what is in the parentheses into the variable of another equation. Let me break that down.

Find

h(4 - n)

if

h(t) = 20 - t.

we know that h is going to be the same no matter what comes after it since it is the same variable. So

h(t) = h(4-n)

which if we look harder, we see that t also equals 4 - n. So now we can take what was in the parentheses (which was 4 - n), and plug it in for t in the second equation.

h(4-n) = 20 - (4 - n)

which will simplify to h(4-n) = 16 + n

Answer 4

Hi Jazmin,

Notice the "4-n" inside the parenthesis on h(4-n), and the "t" inside the parenthesis on h(t). That means we should substitute t with 4-n in order to evaluate h(4-n), so let's do that:

h(4-n) = 20 - (4-n)

=20 - 4 - (-n)

=16 + n